(x+4)^2=3x(x-1)

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Solution for (x+4)^2=3x(x-1) equation: 



(x+4)^2=3x(x-1)

We move all terms to the left:

(x+4)^2-(3x(x-1))=0



We calculate terms in parentheses: -(3x(x-1)), so:

3x(x-1)

We multiply parentheses

3x^2-3x

Back to the equation:

-(3x^2-3x)



We get rid of parentheses

-3x^2+(x+4)^2+3x=0

We add all the numbers together, and all the variables

-3x^2+3x+(x+4)^2=0

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